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libc: Add an implementation of strtol/strtoul and export it via plugins
These were lifted from the lua plugin. sdl, doom, puzzles updated to use the exported version todo: lua, maybe? also: convert uses of atoi [back] to strtol Change-Id: I5a1ebbe8d8c99349e594ab9bbbce474e7645b4e9
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13 changed files with 103 additions and 100 deletions
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@ -22,7 +22,6 @@ float floor_wrapper(float n);
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float atan_wrapper(float x);
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float atan2_wrapper(float y, float x);
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float sqrt_wrapper(float x);
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long strtol_wrapper(const char *nptr, char **endptr, int base);
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int64_t strtoq_wrapper(const char *nptr, char **endptr, int base);
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uint64_t strtouq_wrapper(const char *nptr, char **endptr, int base);
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float pow_wrapper(float x, float y);
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@ -66,7 +65,7 @@ double acos_wrapper(double x);
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#define strcmp rb->strcmp
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#define strcpy rb->strcpy
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#define strlen rb->strlen
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#define strtol strtol_wrapper
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#define strtol rb->strtol
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#define strtoq strtoq_wrapper
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#define strtouq strtouq_wrapper
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#define vsprintf vsprintf_wrapper
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@ -437,101 +437,6 @@ double acos_wrapper(double x)
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*/
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#define CONST const
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long strtol_wrapper(CONST char *nptr, char **endptr, int base)
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{
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register CONST char *s;
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register long acc, cutoff;
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register int c;
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register int neg, any, cutlim;
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/*
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* Skip white space and pick up leading +/- sign if any.
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* If base is 0, allow 0x for hex and 0 for octal, else
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* assume decimal; if base is already 16, allow 0x.
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*/
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s = nptr;
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do {
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c = (unsigned char) *s++;
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} while (isspace(c));
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if (c == '-') {
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neg = 1;
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c = *s++;
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} else {
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neg = 0;
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if (c == '+')
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c = *s++;
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}
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if ((base == 0 || base == 16) && c == '0' && (*s == 'x' || *s == 'X')) {
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c = s[1];
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s += 2;
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base = 16;
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}
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if (base == 0)
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base = c == '0' ? 8 : 10;
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/*
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* Compute the cutoff value between legal numbers and illegal
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* numbers. That is the largest legal value, divided by the
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* base. An input number that is greater than this value, if
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* followed by a legal input character, is too big. One that
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* is equal to this value may be valid or not; the limit
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* between valid and invalid numbers is then based on the last
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* digit. For instance, if the range for longs is
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* [-2147483648..2147483647] and the input base is 10,
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* cutoff will be set to 214748364 and cutlim to either
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* 7 (neg==0) or 8 (neg==1), meaning that if we have accumulated
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* a value > 214748364, or equal but the next digit is > 7 (or 8),
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* the number is too big, and we will return a range error.
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*
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* Set any if any `digits' consumed; make it negative to indicate
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* overflow.
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*/
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cutoff = neg ? LONG_MIN : LONG_MAX;
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cutlim = cutoff % base;
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cutoff /= base;
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if (neg) {
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if (cutlim > 0) {
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cutlim -= base;
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cutoff += 1;
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}
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cutlim = -cutlim;
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}
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for (acc = 0, any = 0;; c = (unsigned char) *s++) {
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if (isdigit(c))
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c -= '0';
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else if (isalpha(c))
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c -= isupper(c) ? 'A' - 10 : 'a' - 10;
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else
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break;
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if (c >= base)
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break;
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if (any < 0)
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continue;
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if (neg) {
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if ((acc < cutoff || acc == cutoff) && c > cutlim) {
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any = -1;
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acc = LONG_MIN;
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} else {
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any = 1;
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acc *= base;
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acc -= c;
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}
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} else {
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if ((acc > cutoff || acc == cutoff) && c > cutlim) {
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any = -1;
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acc = LONG_MAX;
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} else {
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any = 1;
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acc *= base;
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acc += c;
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}
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}
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}
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if (endptr != 0)
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*endptr = (char *) (any ? s - 1 : nptr);
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return (acc);
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}
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int64_t strtoq_wrapper(CONST char *nptr, char **endptr, int base)
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{
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return strtol(nptr, endptr, base);
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