dtc/util.c
Anton Staaf b43335a238 dtc: Refactor character literal parsing code
Move the parsing of hex, octal and escaped characters from data.c
to util.c where it can be used for character literal parsing within
strings as well as for stand alone C style character literals.

Signed-off-by: Anton Staaf <robotboy@chromium.org>
Acked-by: David Gibson <david@gibson.dropbear.id.au>
2011-09-09 16:05:36 -05:00

186 lines
3.6 KiB
C

/*
* Copyright 2008 Jon Loeliger, Freescale Semiconductor, Inc.
*
* util_is_printable_string contributed by
* Pantelis Antoniou <pantelis.antoniou AT gmail.com>
*
* This program is free software; you can redistribute it and/or
* modify it under the terms of the GNU General Public License as
* published by the Free Software Foundation; either version 2 of the
* License, or (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with this program; if not, write to the Free Software
* Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307
* USA
*/
#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include <stdarg.h>
#include <string.h>
#include <assert.h>
#include "util.h"
char *xstrdup(const char *s)
{
int len = strlen(s) + 1;
char *dup = xmalloc(len);
memcpy(dup, s, len);
return dup;
}
char *join_path(const char *path, const char *name)
{
int lenp = strlen(path);
int lenn = strlen(name);
int len;
int needslash = 1;
char *str;
len = lenp + lenn + 2;
if ((lenp > 0) && (path[lenp-1] == '/')) {
needslash = 0;
len--;
}
str = xmalloc(len);
memcpy(str, path, lenp);
if (needslash) {
str[lenp] = '/';
lenp++;
}
memcpy(str+lenp, name, lenn+1);
return str;
}
int util_is_printable_string(const void *data, int len)
{
const char *s = data;
const char *ss;
/* zero length is not */
if (len == 0)
return 0;
/* must terminate with zero */
if (s[len - 1] != '\0')
return 0;
ss = s;
while (*s && isprint(*s))
s++;
/* not zero, or not done yet */
if (*s != '\0' || (s + 1 - ss) < len)
return 0;
return 1;
}
/*
* Parse a octal encoded character starting at index i in string s. The
* resulting character will be returned and the index i will be updated to
* point at the character directly after the end of the encoding, this may be
* the '\0' terminator of the string.
*/
static char get_oct_char(const char *s, int *i)
{
char x[4];
char *endx;
long val;
x[3] = '\0';
strncpy(x, s + *i, 3);
val = strtol(x, &endx, 8);
assert(endx > x);
(*i) += endx - x;
return val;
}
/*
* Parse a hexadecimal encoded character starting at index i in string s. The
* resulting character will be returned and the index i will be updated to
* point at the character directly after the end of the encoding, this may be
* the '\0' terminator of the string.
*/
static char get_hex_char(const char *s, int *i)
{
char x[3];
char *endx;
long val;
x[2] = '\0';
strncpy(x, s + *i, 2);
val = strtol(x, &endx, 16);
if (!(endx > x))
die("\\x used with no following hex digits\n");
(*i) += endx - x;
return val;
}
char get_escape_char(const char *s, int *i)
{
char c = s[*i];
int j = *i + 1;
char val;
assert(c);
switch (c) {
case 'a':
val = '\a';
break;
case 'b':
val = '\b';
break;
case 't':
val = '\t';
break;
case 'n':
val = '\n';
break;
case 'v':
val = '\v';
break;
case 'f':
val = '\f';
break;
case 'r':
val = '\r';
break;
case '0':
case '1':
case '2':
case '3':
case '4':
case '5':
case '6':
case '7':
j--; /* need to re-read the first digit as
* part of the octal value */
val = get_oct_char(s, &j);
break;
case 'x':
val = get_hex_char(s, &j);
break;
default:
val = c;
}
(*i) = j;
return val;
}