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libfdt: Check that there is only one root node

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At present it is possible to have two root nodes and even access nodes
in the 'second' root. Such trees should not be considered valid. This
was discovered as part of a security investigation into U-Boot verified
boot.

Add a check for this to fdt_check_full().

Signed-off-by: Simon Glass <sjg@chromium.org>
Reported-by: Arie Haenel <arie.haenel@intel.com>
Reported-by: Julien Lenoir <julien.lenoir@intel.com>
Message-Id: <20210323000926.3210733-1-sjg@chromium.org>
Signed-off-by: David Gibson <david@gibson.dropbear.id.au>
This commit is contained in:
Simon Glass 2021-03-23 13:09:25 +13:00 • committed by David Gibson
parent 34d708249a
commit 4ca61f84dc
6 changed files with 32 additions and 2 deletions
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4
tests/Makefile.tests
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@ -32,7 +32,9 @@ LIB_TESTS_L = get_mem_rsv \
fs_tree1
LIB_TESTS = $(LIB_TESTS_L:%=$(TESTS_PREFIX)%)
LIBTREE_TESTS_L = truncated_property truncated_string truncated_memrsv
LIBTREE_TESTS_L = truncated_property truncated_string truncated_memrsv \
two_roots
LIBTREE_TESTS = $(LIBTREE_TESTS_L:%=$(TESTS_PREFIX)%)
DL_LIB_TESTS_L = asm_tree_dump value-labels